Question

In the following reaction, 451.4 g of lead reacts with excess oxygen forming 313.6 g of lead(II) oxide. Calculate the percent yield of the reaction.

2Pb(s)+O2(g)= 2PbO(s)

Answer 1

mols Pb = grams/molar mas = ?
Use the coefficients in the balanced equation to convert mols Pb to mols PbO
Now convert mols PbO to g. g = mols x molar mass. This is the theoretical yield (TY)
%yield = (actual yield/TY)*100 = ?

Answer 2

I'm so confused...how do I use the coefficients to balance the equations?