Asked by Anonymous
Car traveling on circular track. Point A is at positive x,y. Point B is at positive x, negative y.
A car is traveling around a horizontal circular track with radius r = 220 m as shown. It takes the car t = 51 s to go around the track once. The angle èA = 31° above the x axis, and the angle èB = 56° below the x axis.
1)
What is the magnitude of the car’s acceleration?
A car is traveling around a horizontal circular track with radius r = 220 m as shown. It takes the car t = 51 s to go around the track once. The angle èA = 31° above the x axis, and the angle èB = 56° below the x axis.
1)
What is the magnitude of the car’s acceleration?
Answers
Answered by
Anonymous
2*3.14*220 = d
v= d/t ( put d and t=51 )
a = v^2/r ( r 220 ).
v= d/t ( put d and t=51 )
a = v^2/r ( r 220 ).
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