Asked by Rebekah

solve for dv/du

dQ/du= 38u + [(u+v)^2(18+19dv/du) -(2(18u+19v)(u+v)(1+dv/du)]/ (u+v)^4

u=10 v=25

I am confused how u solve for the dv/du in this big equation and reducing and stuff like that

thanks!! this is about implicit di

Answers

Answered by Reiny
looking at the pattern of your answer, it looks like there were 2 terms and the quotient rule was used on the second term

looks like you had

Q = 19u^2 + (18u+19v(/(u+v)^2
and you took the derivative with respect to u

since you know the value of u and v, you can shave down that messy looking right side quite a bit

dQ/du = 380 + [ 35^2(18 + 19dv/du) - 2(655)(25)(1+dv/du) ] 35^4
If you were somehow finding max/min, then dQ/du would be zero, otherwise I don't know what value the left side is
But you have a calculator, just crunch out the numbers. You will have to distribute 35^(18+19dv/du) and the second part of the numerator to get at the dv/du, but hang in there.
Eventually you will be able to collect the dv/du terms, since the other parts are constants.
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