Asked by Matt
                For the following electrochemical cell:
Fe(s)/Fe2+(aq)//MnO4–(aq), Mn2+(aq)/ Pt(s)
Which letter corresponds to the correct balanced chemical equation in an acidic solution?
A. 2Mn2+(aq) + 8H2O(l) + 5Fe2+ ==> (aq)5Fe(s) + 16H+(aq) + 2MnO4–(aq)
B. 5Fe(s) + 16H+(aq) + 2MnO4–(aq)2Mn2+(aq) + 8H2O(l) + 5Fe2+(aq)
C. Fe(s) + 8H+(aq) + MnO4–(aq) ==> Mn2+(aq) + 4H2O(l) + Fe2+(aq)
D. Fe(s)+8H+(aq)+MnO4–(aq)+Pt2+(aq)==> Mn2+(aq)+4H2O(l)+Fe2+(aq)+Pt(s)
E. Mn2+(aq)+4H2O(l)+Fe2+(aq)+Pt(s) ==>Fe(s)+8H+(aq)+MnO4–(aq)+Pt2+(aq)
What reaction is occurring at the cathode?
A. 5e– + 8H+(aq)+MnO4–(aq)==>Mn2+(aq) +4H2O(l)
B. Fe2+(aq) + 2e– ==> Fe(s)
C. Fe(s)==>Fe2+(aq) + 2e–
D. Mn2+(aq) + 4H2O(l)==>5e– + 8H+(aq) + MnO4–(aq)
E. Pt(s)==>Pt2+ + 2e
            
        Fe(s)/Fe2+(aq)//MnO4–(aq), Mn2+(aq)/ Pt(s)
Which letter corresponds to the correct balanced chemical equation in an acidic solution?
A. 2Mn2+(aq) + 8H2O(l) + 5Fe2+ ==> (aq)5Fe(s) + 16H+(aq) + 2MnO4–(aq)
B. 5Fe(s) + 16H+(aq) + 2MnO4–(aq)2Mn2+(aq) + 8H2O(l) + 5Fe2+(aq)
C. Fe(s) + 8H+(aq) + MnO4–(aq) ==> Mn2+(aq) + 4H2O(l) + Fe2+(aq)
D. Fe(s)+8H+(aq)+MnO4–(aq)+Pt2+(aq)==> Mn2+(aq)+4H2O(l)+Fe2+(aq)+Pt(s)
E. Mn2+(aq)+4H2O(l)+Fe2+(aq)+Pt(s) ==>Fe(s)+8H+(aq)+MnO4–(aq)+Pt2+(aq)
What reaction is occurring at the cathode?
A. 5e– + 8H+(aq)+MnO4–(aq)==>Mn2+(aq) +4H2O(l)
B. Fe2+(aq) + 2e– ==> Fe(s)
C. Fe(s)==>Fe2+(aq) + 2e–
D. Mn2+(aq) + 4H2O(l)==>5e– + 8H+(aq) + MnO4–(aq)
E. Pt(s)==>Pt2+ + 2e
Answers
                    Answered by
            DrBob222
            
    What do you think and why? 
#2. Reduction occurs at the cathode (the + charged electrode).
    
#2. Reduction occurs at the cathode (the + charged electrode).
                    Answered by
            Matt
            
    #1, Fe(s) is on the left, so it's anode; Pt(s) is on the right, it's a cathode...so  the rxn should be D. 
#2: B because Fe is gaining electrons, making it a reduction=cathode.
    
#2: B because Fe is gaining electrons, making it a reduction=cathode.
                    Answered by
            DrBob222
            
    Right on the anode and cathode. If D is the correct answer, why doesn't it have Fe in it. There's no Fe in D. And you need an Fe going to Fe^+2 + 2e.
    
                    Answered by
            Matt
            
    no, there's Fe in D for the first question..Fe(s)+8H+(aq)+MnO4–(aq)+Pt2+(aq)==> Mn2+(aq)+4H2O(l)+Fe2+(aq)+Pt(s) 
    
                    Answered by
            DrBob222
            
    You're right and I'm wrong. I was looking at the second set of answers and not the first. So Fe is on the left and it is the anode. So now what reaction is occurring at the Pt electrode? Obviously it's the other half cell, which is______?
    
                    Answered by
            Matt
            
    Pt is functioning as a cathode
- D shows that Pt is cathode and Fe as anode. I don't understand why H+ and water are in the reaction
so my answers
1)D
2)B
    
- D shows that Pt is cathode and Fe as anode. I don't understand why H+ and water are in the reaction
so my answers
1)D
2)B
                    Answered by
            DrBob222
            
    D is correct for #1. For #2, isn't the correct answer A? Pt is the cathode (+ electrode where reduction occurs) and that is the MnO4^- reaction going to Mn^+2.
    
                    Answered by
            RoRo
            
    the answer is actually B and A
    
                    Answered by
            yi
            
    isn't Pt just functioning as an electrode? 
    
                    Answered by
            UCI Student
            
    answer is B and A
    
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