Find the unknown in the following equation. If there are more than one solution, then separate the solutions with a comma.

Question

(−8y−4)^2+10=14

y=?

I keep on getting y=-0.5, is that correct?

Answer 1

well, does it satisfy the equation?
(-8(-.5)-4)^2+10
= (4-4)^2+10
= 0+10
= 10
BZZZZT!

Try this:

(−8y−4)^2+10=14
(−8y−4)^2=4
-8y-4 = ±2
-8y = 4±2 = 6 or 2
y = -6/8 or -2/8
y = -3/4 or -1/4
Nope, -1/2 is not a solution

Answer 2

thanks I figured out what I did wrong