If a ball has an initial speed of 26.9 m/s and is launched at an angle of 63.2 degrees above the horizontal, what is the tallest obstacle that the ball can clear?

Answer 1

Vo = 26.9m/s[63.2o]
Xo = 26.9*cos63.2 = 12.13 m/s.
Yo = 26.9*sin63.2 = 24.01 m/s.

Y^2 = Yo^2 + 2g*h
h = (Y^2-Yo^2)/2g = (0-24.01^2)/-19.6 =
29.41 m.