Asked by Nikolina

Victor drove his truck off a cliff that was 45m high, and it landed 35m from the base of the cliff. What was the velocity of the truck as it drove off the cliff?

Answers

Answered by Henry
h = Vo*t + 0.5g*t%2 = 45 m.
h = 4.9t^2 = 45
t^2 = 9.18
Tf = 3.03 s. = Fall time.

Dist. = Xo * Tf = 35 m.
Xo * 3.03 = 35
Xo = 11.55 m/s = Hor. component of initial velocity. Yo = 0.

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