Asked by Nikolina
Victor drove his truck off a cliff that was 45m high, and it landed 35m from the base of the cliff. What was the velocity of the truck as it drove off the cliff?
Answers
Answered by
Henry
h = Vo*t + 0.5g*t%2 = 45 m.
h = 4.9t^2 = 45
t^2 = 9.18
Tf = 3.03 s. = Fall time.
Dist. = Xo * Tf = 35 m.
Xo * 3.03 = 35
Xo = 11.55 m/s = Hor. component of initial velocity. Yo = 0.
h = 4.9t^2 = 45
t^2 = 9.18
Tf = 3.03 s. = Fall time.
Dist. = Xo * Tf = 35 m.
Xo * 3.03 = 35
Xo = 11.55 m/s = Hor. component of initial velocity. Yo = 0.
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