Asked by Jamie
                I am trying to figure out the molecular, ionic, and net equation for this question.
HCl reacts with the precipitate formed from mixing Ni(NO3)2 and NaOH .
This is what I got for the molecular but it is saying it wrong. Please help. Thank you.
HCl(aq) + Ni(NO3)2(aq) + NaOH(aq) --> Ni(OH2)(s) + NaNO3(aq) + NiCl2(aq) + H2O(l)
            
        HCl reacts with the precipitate formed from mixing Ni(NO3)2 and NaOH .
This is what I got for the molecular but it is saying it wrong. Please help. Thank you.
HCl(aq) + Ni(NO3)2(aq) + NaOH(aq) --> Ni(OH2)(s) + NaNO3(aq) + NiCl2(aq) + H2O(l)
Answers
                    Answered by
            DrBob222
            
    I think you probably want two reactions.
1.
Ni(NO3)2 + + 2NaOH ==> Ni(OH)2(s) + 2NaNO3
Then 2 is:
Ni(OH)2 + 2HCl ==> NiCl2 + 2H2O
Then convert that last balanced molecula equation to the ionic then to the net ionic equation.
    
1.
Ni(NO3)2 + + 2NaOH ==> Ni(OH)2(s) + 2NaNO3
Then 2 is:
Ni(OH)2 + 2HCl ==> NiCl2 + 2H2O
Then convert that last balanced molecula equation to the ionic then to the net ionic equation.
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