The first two need to be non-Jacks.
First card = (52-4)/52
With one card gone, the second card = (51-4)/51
The third card needs to be the Jack = 4/50
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
You are dealt a hand of three cards, one at a time. Find the probability that your third card is your first jack.
A) 0.068
B) 0.145
C) 0.127
D) 0.077
E) 0.00018
How do I set this problem up?
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