Question

A 74 kg box rests on a level surface. The coefficient of static friction, µS = 1.1 and the coefficient of kinetic friction, µK = 0.7 . What is the magnitude of Friction on the box from the surface?
Wb = m * g = 74kg * 9.8N/kg = 725.2 N. =
Weight of box.

Fs = u * Wb = 1.1 * 725.2 = 797.7 N. =
Force of static friction.

Related Questions

If a block of mass 10.0 kg rests on a horizontal surface, and the coefficient of static friction is... One block rests upon a horizontal surface. A second identical block rests upon the first one. The co... A 100-kg object rests on a level surface with a coefficient of friction (both kinetic and static) of...