Asked by jerri
solve by the quadriatic formula, Im still trying to figure how to do this can someone please help me.
(5x+1)^2 + 13=0
(5x+1)^2 + 13=0
Answers
Answered by
Steve
to use the QF, first expand things
25x^2 + 10x + 1 + 13 = 0
25x^2 + 10x + 14 = 0
Now just plug your numbers into the QF. The roots will be complex, as you can easily see since
(5x+1)^2 = -13
but the left side is always positive, meaning there are no real solutions.
25x^2 + 10x + 1 + 13 = 0
25x^2 + 10x + 14 = 0
Now just plug your numbers into the QF. The roots will be complex, as you can easily see since
(5x+1)^2 = -13
but the left side is always positive, meaning there are no real solutions.