Asked by OwamIIi
Determine the general solution of 8cos^2x-1=0
Answers
Answered by
Steve
(√8 cosx-1)(√8 cosx+1) = 0
cosx = ±1/√8
x = n*pi ± arccos(1/√8)
or
x = n*pi ± 1/2 arccos(-3/4)
cosx = ±1/√8
x = n*pi ± arccos(1/√8)
or
x = n*pi ± 1/2 arccos(-3/4)
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