Asked by plzhelp
Calculate the value of the equilibrium constant (Kc) for the reaction shown, if NO2(g) was found to be 95.54 % decomposed at 45.00 °C when its initial concentration was 5.725 mol/L. The initial concentration of the reaction products is 0 mol/L.
2NO2(g) = N2O4(g)
2NO2(g) = N2O4(g)
Answers
Answered by
DrBob222
.........2NO2 ==> N2O4
I.........5.725.....0
C.......-5.470...+2.735
E.......0.2553.......2.735
Substitute into Kc expression and solve.
Note: Initial NO2 is 5.725M
5.725*0.9554 = 5.470 decomposed.
The N2O4 is 1/2 that.
I.........5.725.....0
C.......-5.470...+2.735
E.......0.2553.......2.735
Substitute into Kc expression and solve.
Note: Initial NO2 is 5.725M
5.725*0.9554 = 5.470 decomposed.
The N2O4 is 1/2 that.
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