centripetal acceleration is v^2/r everywhere on the circle.
Tension=ma+-mv^2/r
at the bottom, +, at the top, -
For circular motion in the vertical plane, what is the centripital acceleration at the bottom of the circle?
What is the magnitude of the centripetal acceleration at the top of the trajectory ?
express your ans. in terms of g, M and T,
where is T is tension and M is mass of the object. If we move the mass attached to a rope in vertical circular motion
1 answer
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