Asked by Anonymous

how many millimeters of a 5.15 M CH3OH stock solution are needed to prepare 375 mL of a solution having 7.50 mg of methanol per mL of solution

12 years ago

Answered by Anonymous

17 mL

12 years ago

Answered by DrBob222

I ran through it and obtained 17.06 mL which I would round to 17.1 mL.

12 years ago

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