Asked by Anonymous

how many millimeters of a 5.15 M CH3OH stock solution are needed to prepare 375 mL of a solution having 7.50 mg of methanol per mL of solution

Answers

Answered by Anonymous
17 mL
Answered by DrBob222
I ran through it and obtained 17.06 mL which I would round to 17.1 mL.
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