Asked by Joe

When a 0.101 kg mass is suspended at rest from a certain spring, the spring stretches 3.80 cm. Find the instantaneous acceleration of the mass when it is raised 5.90 cm, compressing the spring 2.10 cm.
Answered by Joe
Yes
Answered by bobpursley
w=kx
.101g=k*3.80

k=.101g/3.80

force of compression=
= (.101g/.0389)(.0590-.0380)
figure that out, then
using f=ma or a=f/m
and we have to add g because the object is going down,

a=g+(.101g/.0389)(.0590-.0380) /.101g)