(time given is the total time in the air, up and

down)
During a baseball game, a batter hits a high
pop-up.
If the ball remains in the air for 4.84 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s2 .
Answer in units of m

1 answer

Tr = 0.5 * 4.84 = 2.42 s. = Rise time.
V = Vo + g.t = 0 @ max ht.
Vo - 9.8*(2.42) = 0
Vo = 23.72 m/s. = Initial velocity.

h = Vo*t + 0.5g*t^2
h = 23.72*2.42 - 4.9*2.42^2 = 28.7 m.
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