Asked by Sam
How would you solve these compound inequalities?
1. -5k<-10 OR 3k>-9
2. 1/2z+3<-4 OR 2/3z-1>=1/5
3. -2<=n+2 divided by 3 <=4
4.p+4>6 AND 3p<=-18
1. -5k<-10 OR 3k>-9
2. 1/2z+3<-4 OR 2/3z-1>=1/5
3. -2<=n+2 divided by 3 <=4
4.p+4>6 AND 3p<=-18
Answers
Answered by
Anonymous
-5k < -10
÷(-5) ÷(-5)
(^ cancels out bring down 'k')
(Switch symbol becuz u divided b a negative)
K > 2
÷(-5) ÷(-5)
(^ cancels out bring down 'k')
(Switch symbol becuz u divided b a negative)
K > 2