Asked by Julie
A 50mL solution of NaOH is neutralized by adding 37.5 mL of 0.045 M HCL. What was the original concentration of the NaOH solution?
Answers
Answered by
DrBob222
Write the equation and balance it.
mols HCl = M x L = ?
Using the coefficients in the balanced equation, convert mols HCl to mols NaOH. Then, M NaOH = mols NaOH/L NaOH
mols HCl = M x L = ?
Using the coefficients in the balanced equation, convert mols HCl to mols NaOH. Then, M NaOH = mols NaOH/L NaOH
Answered by
Julie
What is the balanced equation? I cant figure out the answer
Answered by
DrBob222
HCl is an acid.
NaOH is a base.
general equation is as follows:
an acid + a base = salt + water
HCl + NaOH ==> NaCl + H2O
NaOH is a base.
general equation is as follows:
an acid + a base = salt + water
HCl + NaOH ==> NaCl + H2O
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