Question
A standard deck of cards contains 52 cards. Of these cards there are 13 of each type of suit (hearts, spades, clubs, diamonds) and 4 of each type of rank (A – K). Two cards are pulled in order from this deck of 52 playing cards. What is the probability that the cards will be two 10’s?
Answers
number of ways to choose 2 of the 4 tens
= C(4,2) = 6
(HS, HC, HD, SC, SD, CD)
number of ways to choose 2 cards from the 52
= C(52,2) = 1326
prob 2 tens = 6/1326 = 1/221
or
prob of first card a ten = 4/52
prob of 2dn card a ten = 3/51
prob 2 tens = (4/52)(3/51) = 12/2652 = 1/221
= C(4,2) = 6
(HS, HC, HD, SC, SD, CD)
number of ways to choose 2 cards from the 52
= C(52,2) = 1326
prob 2 tens = 6/1326 = 1/221
or
prob of first card a ten = 4/52
prob of 2dn card a ten = 3/51
prob 2 tens = (4/52)(3/51) = 12/2652 = 1/221
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