Asked by girlwithaquestion
How many revolutions per minute would a 16m -diameter Ferris wheel need to make for the passengers to feel "weightless" at the topmost point?
All I want to know is where do I start?
I thought I would set a(centripital accelteration) = (9.8 m/s^2)?
All I want to know is where do I start?
I thought I would set a(centripital accelteration) = (9.8 m/s^2)?
Answers
Answered by
girlwithaquestion
Oops nevermind realized I was using 2(pi)r^2 and not 2(pi)r.
Answered by
girlwithaquestion
So set a(c) = 9.8, and use a= v^2/r so find v. Then, use the equation for velocity.
Answered by
scott
your calculated v will be in m/s
the question asks for rpm
60 s in a min and circumference = 2πr
(60 v) / (2 π r)
the question asks for rpm
60 s in a min and circumference = 2πr
(60 v) / (2 π r)
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