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Asked by Anonymous

lim radical 6-x)-2/radical 3-x)-1=
12 years ago

Answers

Answered by Steve
(√(6-x)-2)/(√(3-x)-1)
I assume the limit is as x->2, otherwise there's no problem.

Use l'Hospital's Rule to get

-1/2√(6-x) / -1/2√(3-x)
= √((3-x)/(6-x))
= √(1/4)
= 1/2
12 years ago

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