Asked by Taylor
Use integration by parts to evaluate the integral xsqrt(2x+6)dx.
Answers
Answered by
Steve
∫x√(2x+6) dx
u = x
du = dx
dv = √(2x+6) dx
v = 1/3 (2x+6)^(3/2)
∫u dv = uv - ∫v du
and plug and chug
u = x
du = dx
dv = √(2x+6) dx
v = 1/3 (2x+6)^(3/2)
∫u dv = uv - ∫v du
and plug and chug
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