Question

(5^2-16w+3)/5w^2+24w-5)*(15w^2-8w+1)/(3w^2+14w-5)

Answer 1

There might have been some typos in your question, so I interpreted it as
((5x^2-16x+3)/(5x^2+24x-5))*((15x^2-8x+1)/(3x^2+14x-5))

We factor each quadratic equation inside the parenthesis, and simplify.
((5x^2-16x+3)/(5x^2+24x-5))*((15x^2-8x+1)/(3x^2+14x-5))
((5x-1)(x-3)/(5x-1)(x+5))*((3x-1)(5x-1)/(3x-1)(x+5))
Terms that will be cancelled: 5x-1 and 3x-1
Thus,
(x-3)(5x-1) / ((x+5)(x+5))
And replace the variable x with w.

Hope this helps~ :3

Answer 2

Yes, it does. Thanks so much