Asked by Anonymous
How do you find x and y intercepts for y=x-2/x+3
Answers
Answered by
Reiny
did you mean it the way you typed it, or did you mean
y = (x-2)/(x+3)
It really, really matters
e.g. if x = 7
yours: y = 7 - 2/7 + 3 = 10 - 2/7 = 68/7
mine: y = (7-2)/(7+3) = 5/10 = 1/2
y = (x-2)/(x+3)
It really, really matters
e.g. if x = 7
yours: y = 7 - 2/7 + 3 = 10 - 2/7 = 68/7
mine: y = (7-2)/(7+3) = 5/10 = 1/2
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