Given:
v1 = 34.5 [cos(50°) W + sin(50°) N] km/hr
v2 = 16.1 [0 W + 1 N] km/hr
Let: s = 3 v1 + 0.5 v2
Find: |s|
s = (3*34.5*cos(50°)) W + (3*35.6sin(50°)+0.5*16.1) N
|s| = √((3*34.5*cos(50°))^2 + (3*35.6sin(50°)+0.5*16.1)^2)
The eye of a hurricane passes over Grand Bahama Island. It is moving in a direction θ = 50° north of west with speed v1 = 34.5 km/h. Exactly three hours later, the course of the hurricane shifts due north, and its speed slows to v2 = 16.1 km/h, as shown below. How far from Grand Bahama is the hurricane 3.5 h after it passes over the island?
2 answers
yes