Asked by Krystal
For the period 1990-2002, the number s (in thousands)lf cellular telephone subscribers in the United States can be modified by S=858t^2 + 1412t + 4982 where t is the number of years since 1990. In what year did the number of subscribers reach 50 million?
The choices are the year 1991, 1992, 1996, or 2000.
I've tried the quadratic formula and tried finding the discriminant of the quadratic equation but I can't get one of the given answers. Can someone show me how to do this problem?
The choices are the year 1991, 1992, 1996, or 2000.
I've tried the quadratic formula and tried finding the discriminant of the quadratic equation but I can't get one of the given answers. Can someone show me how to do this problem?
Answers
Answered by
Reiny
The discriminant does not give you the solution, it is part of the formula that gets you the solution.
858t^2 + 1412t + 4982 = 50000
858t^2 + 1412t - 45018 = 0
t = (-1412 ± 12509.81695)/1716
= 6.46 years since 1990
= 6 years rounded to nearest year
so it would be the year 1996
858t^2 + 1412t + 4982 = 50000
858t^2 + 1412t - 45018 = 0
t = (-1412 ± 12509.81695)/1716
= 6.46 years since 1990
= 6 years rounded to nearest year
so it would be the year 1996
Answered by
Krystal
How do you get 50000?
Answered by
Reiny
numbers used are expressed in thousands, you said so.
So 50 million in thousands = 50 000 000/1000 = 50000
So 50 million in thousands = 50 000 000/1000 = 50000
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