Matt Ashell, world famous downhill skier, waxed his skis with the wrong kind of wax and ended up with a relatively high coefficient of friction of 0.40. If Matt, who weights 667.5 N is on a downhill slope of 38 degrees, will he slide without a push?

Answer 1

mg = 667.5 N.

F1 = mg*sinA = 667.5*sin38 = 411 N = Force parallel to the hill.
F2 = mg*sinA= 667.5*cos38 = 526 N = Force perpendicular to the hill.

Fs = u*F2 = 0.4 * 526 = 210.4 N = Force of static friction.

Yes, because F1 is greater than the forceof s tatic friction, Fs.

Answer 2

Correction: F2 = mg*cosA.