Question
Neon-20 has a nuclear mass of 19.992439 amu. the total nuclear binding energy for Ne-20 is?
(Mprotons=1.6726x10^-27 kg) (Mneutron=1.6749x10^-27kg)
(Mprotons=1.6726x10^-27 kg) (Mneutron=1.6749x10^-27kg)
Answers
Elena
1 amu = 1.6605•10⁻²⁷ kg
19.992439 amu = 3.3197•10⁻²⁶ kg
m=10 m(p) +10 m(n) =
=10• (1.6726+1.6749) •10⁻²⁷ =
=3.3475•10⁻²⁶ kg
Δm=(3.3475-3.3197) •10⁻²⁶=
=0.027810⁻²⁶=2.78•10⁻²⁸ kg
E= Δm•c² =2.78•10⁻²⁸•(3•10⁸)² =2.502•10⁻¹¹ J.
19.992439 amu = 3.3197•10⁻²⁶ kg
m=10 m(p) +10 m(n) =
=10• (1.6726+1.6749) •10⁻²⁷ =
=3.3475•10⁻²⁶ kg
Δm=(3.3475-3.3197) •10⁻²⁶=
=0.027810⁻²⁶=2.78•10⁻²⁸ kg
E= Δm•c² =2.78•10⁻²⁸•(3•10⁸)² =2.502•10⁻¹¹ J.