Asked by Antony

A lead atom has a mass of 3.4⋅10^-22 g. How many lead atoms are in a cube of lead that has a volume of 2.07 cm^3 if the density of lead is 11.3 g/cm^3?
Answered by DrBob222
volume = 2.07 cc
density = 11.3
mass = volume x density = 2.07 x 11.3 = about 23g but you should be more exact than that.
Then 3.4E-22 x # Pb atoms = about 23 g
Solve for # Pb atoms.
Answered by Antony
so, is it equal 6.9*10^22 ?
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