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Two cars, A and B, are traveling in the same direction, although car A is 204 m behind car B. The speed of A is 22.9 m/s, and the speed of B is 18.6 m/s. How much time does it take for A to catch B?

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Da = 204 + Db
Da = 22.9t = 204 + 18.6t
22.9t-18.6t = 204
4.3t = 204
t = 47.44 s. To catch up.

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