Asked by Anonymous
An element with the symbol Z has the electron configuration 2.8.6. Which species is this elrment most likely to form?
A. The ion Z 2+
B. The ion Z 6+
C. The compound H subscript 2 Z
D. The compound Z subscript 6 F
Which ionization requires the most energy?
A. Na--> Na superscript + plus one electron
B. Na superscript + -----> Na superscript 2+ plus one electron
C. Mg---> Mg superscript + plus one electron
D. Mg superscript + -----> Mg superscript 2+ plus one electron
A. The ion Z 2+
B. The ion Z 6+
C. The compound H subscript 2 Z
D. The compound Z subscript 6 F
Which ionization requires the most energy?
A. Na--> Na superscript + plus one electron
B. Na superscript + -----> Na superscript 2+ plus one electron
C. Mg---> Mg superscript + plus one electron
D. Mg superscript + -----> Mg superscript 2+ plus one electron
Answers
Answered by
DrBob222
For 2.8.6 we would expect
1s2 2s2 2p6 3s2 3p4 which puts the element in group 16 (or VI) it probably is S. It could form +6 but is more likely to form -2 so H2Z is what I would pick.
It might also form ZF6 (but not Z6F) but H2S is still the most probable.
Would #2 make sense to go with B?
1s2 2s2 2p6 3s2 3p4 which puts the element in group 16 (or VI) it probably is S. It could form +6 but is more likely to form -2 so H2Z is what I would pick.
It might also form ZF6 (but not Z6F) but H2S is still the most probable.
Would #2 make sense to go with B?
Answered by
lula
A. The ion Z2+
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