Question

Calculates the work done (in joules) when 42.8 g of tin dissolves in excess acid at 1.10 atm and 23 degrees Celcius. Assume ideal gas behaviour.

Answer 1

Try this.
Sn + 2HCl ==> SnCl2 + H2
mols Sn = 42.8/atomic mass Sn
mols H2 = mols Sn
Then PV = nRT
You know n, R, T, solve for PV and that is work of expansion of the gas. The unit is L*atm. Multiply by 101.325 to convert to joules.