Question

The enthalpy of vaporization of benzene liquid is 33.9 kJ/mol at 298 K.

How many liters of benzene gas, measured at 298 K and 95.1 mmHg, are formed when 1.54 kJ of heat is absorbed by benzene liquid at a constant temperature of 298 K?

I think we use the ideal gas law, but I'm not sure what to do with the heat.
33.9 kJ/mol x ? mol = 1.54 kJ
Solve for ?mol benzene, then substitute into PV = nRT and solve for volume in L.

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