Asked by Frank
How many grams of sodium sulphate (mol. wt. 142) are required to make 1.2 liters of 0.5N solution
Answers
Answered by
DrBob222
Technically one can't calculate this without knowing the reaction involved; however, is most problems of this type the usual is to use total + and - charge.
Therefore, equivalent weight Na2SO4 = molar mass/+ charge = 142/2 = 81.
How many equivalents do you need? That's
N x L = 0.5N x 1.2L = ?
Then ?equivalent x equivalent weight = grams Na2SO4.
Therefore, equivalent weight Na2SO4 = molar mass/+ charge = 142/2 = 81.
How many equivalents do you need? That's
N x L = 0.5N x 1.2L = ?
Then ?equivalent x equivalent weight = grams Na2SO4.
Answered by
reggie
48.6
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