[(1/4)^-3 ÷ (1/4)^2]^-2
inside the square brackets we are dividing powers with the same base, so keep the base and subtract the exponents
= [ (1/4)^(-3 -2) ]^2
= [(1/4)^-5]^2
= (1/4)^-10
= 4^10
(3^1/2)^3
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9
= 3^(3/2) / 3^2
= 3^(3/2-2)
= 3^(-1/2) = 1/3^(1/2) or 1/√3
(-56r^2) ÷ (-7r^2)
= (-56r^2)/(-7r^2)
= 8
How did you get 8r, there is an r^2 on top and r^2 at the bottom so they divide out to get 1
For the rest of the questions, I can't tell where one ends and the next one begins
for all the questions beginning with "simplify", did you not notice that in each case you are taking the square root of a perfect square ?
e.g.
simplify 3√81 = 3(9) = 27
etc
Here are the questions I need help with, please help.
[(1/4)^-3 divide sign (1/4)^2]^-2
I got (1/4)^10 but I got it wrong
(3^1/2)^3
_______ I got 1/216
9
(-56r^2)divide sign (-7r^2)= I got 8r
x(y)(x)(2y)
(12) (10xy^3) (3x^2y^2) (5x) (2y)
simplify sqaure root of 160000
simplify sqaure root of 0.04
simplify 3 * square root 81
simplify square root of 900
simplify square root of 0.0025simplify [(a^2bc^4)(ab^3c^2)]^2
___________________
(b^2c^5)^3
what is 4^-5/2 expressed as a radical with positive exponents
Thank you so much
1 answer
2 answers