k = 0.693/t1/2
Then
ln(No/N) = kt
No = 200 mg
N = solve for this
k from above
t time i hours.
Technetium-99m is an ideal radioisotope for scanning organs because it has a half-life of 6.0 hr and is a pure gamma emitter. Suppose that 200mg were prepared in the technetium generator this morning. How many milligrams would remain after the following intervals?
1- One half life.
2- two half-lives
3- 18 hr
4- 30 hr
1 answer
2 answers