Asked by kristy

A rifle that shoots bullets at 404 m/s is to be aimed at a target 49.7 m away. If the center of the target is level with the rifle, how high (in cm) above the target must the rifle barrel be pointed so that the bullet hits dead center?

Answers

Answered by Steve
The range is
R = v^2 sin2θ / g

so,
404^2 sin2θ /9.8 = 49.7
sin2θ = 9.8*49.7/404^2 = .00298
θ = 0.085°

not much of an elevation
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions