Question
find the slope m and an equation of the tangent line to the graph of the function f at the specified point.
original: x^2/x+10 point: (3,9/13)
After I found the derivative: (x+10)(2x)-(x^2)(1)/((x+10))^2
How do I get the slope? Should I put 3 into the derivative equation?
original: x^2/x+10 point: (3,9/13)
After I found the derivative: (x+10)(2x)-(x^2)(1)/((x+10))^2
How do I get the slope? Should I put 3 into the derivative equation?