Asked by Nico
to find value of x and discontinous 9x²-3x-2/3x²+13x-4
Answers
Answered by
Steve
3x^2+13x-4 = 0 when x = -1/6 (13±√217)
9x^2-3x-2 = (3x-2)(3x+1)
so, f(x) is discontinuous at x = -1/6 (13±√217) where the denominator is zero.
9x^2-3x-2 = (3x-2)(3x+1)
so, f(x) is discontinuous at x = -1/6 (13±√217) where the denominator is zero.
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