h = 117*sin 31 = 60.26 m.
V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*60.26 = 1181.09
V = 34.37 m/s
A 45 kg child sits on a 5 kg sled and slides down a 117 meter, 31 degree slope, to the nearest m/s what is his or her speed at the bottom?
1 answer