Asked by Alaska Diamond
0>x^2 +5x -2
Can someone help me solve for x and show me the steps please
Can someone help me solve for x and show me the steps please
Answers
Answered by
MathGuru
Using the quadratic formula, we have:
[-b +/- √(b^2 - 4ac)] / 2a
a = 1; b = 5; c = -2
[-5 +/- √(5^2 - 4 * 1 * -2)] / 2*1
x > (-5 - √33)/2
x < (-5 + √33)/2
Therefore:
(-5 - √33)/2 < x < (-5 + √33)/2
Check this!
[-b +/- √(b^2 - 4ac)] / 2a
a = 1; b = 5; c = -2
[-5 +/- √(5^2 - 4 * 1 * -2)] / 2*1
x > (-5 - √33)/2
x < (-5 + √33)/2
Therefore:
(-5 - √33)/2 < x < (-5 + √33)/2
Check this!
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