Asked by Anonymous
What should be the angle between two vectors of magnitudes 3.20 and 5.70 units, so that their resultant has a magnitude of 6.10 units?
cos=a^2+b^2-c^2/2ab
cos10.24+32.49-37.21/(2*3.20*5.70)
= 99 degrees
cos=a^2+b^2-c^2/2ab
cos10.24+32.49-37.21/(2*3.20*5.70)
= 99 degrees
Answers
Answered by
Damon
yes, 180 - 81.3 = 98.7
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