Question

f(x)= 1/x^2-8x-9
g(x)= 1/x^2+3x+2

Answer 1

What is required to find? :3

Answer 2

Domain

Answer 3

Domain of what?
If the required is their individual domains:
1. For f(x) = 1/(x^2 - 8x - 9)
Note that domain is the set of all possible values of x. In the function, note that the denominator must not be equal to zero because 1/0 is infinity. Therefore, we find the values of x, which the denominator will be zero and restrict the domain to those values:
f(x) = 1/(x^2 - 8x - 9)
f(x) = 1/(x-9)(x+1)
Thus, x is all real numbers except -1 and 9.

2. For g(x) = 1/(x^2 + 3x + 2)
The procedure is pretty much the same. We find the values of x which will make the denominator zero:
g(x) = 1/(x^2 + 3x + 2)
g(x) = 1/(x+1)(x+2)
Thus, x is all real number except -1 and -2.

Hope this helps~ :3