Find the value of k so that the line containing the points (k,−8) and (−3,−5) is parallel to the line containing the points (9,7) and (12,5).

Answer 1

(k,-8), (-3.-5).
(9,7), (12,5).

m1 = m2 = (5-7)/(12-9) = -2/3.

m1 = (-5-(-8))/(-3-k) = -2/3
(-5+8)/(-3-k) = -2/3
3/(-3-k) = -2/3
6+2k = 9
2k = 3
k = 3/2.