Question

Surprisingly, very few athletes can jump more than 2.7 ft (0.82 m) straight up. Use d = 1/2 gt2 and solve for the time one spends moving upward in a 0.82 m vertical jump. Then double it for the "hang-time" -- the time one's feet are off the ground.
Can you explain step by step please.

Answer 1

Use: d = (1/2) gt^2
Where: g = -9.8[m/s^2]
Given: d = 0.82[m]
Find: t

Just rearrange the equation and substitute for the given values.

Answer 2

d=(1/2)gt^2
g=-9.8m/s^2
d=0.82
what about 2.7 ft?

Answer 3

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