Asked by Gabriella

Given the Na+/Na and K+/K half-cells, determine the overall electrochemical reaction that proceeds spontaneously and the E0 value.
Answer in units of V
Answered by DrBob222
Is this all of the problem? Do you want the Na ==> Na^+ + e or the
Na + K^+ ==> K + Na^+ rxn?
Do you have the half cells potentials?
Answered by Gabriella
Na half-cell potential is -2.71
K half-cell potential is -2.92
and yes that is all of the problem
Answered by DrBob222
K ==> K^+ + e Eo = +2.92
Na^+ + e ==> Na Eo = -2.71
--------------------------
K + Na^+ ==> K^+ + Na Eocell = +0.21 v.

The cell as written is spontaneous since Eo cell is positive.
Answered by Anonymous
.21v
Answered by Anonymous
.22 is the write answer
Answered by Ann
0.22 is corect
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