95.0 mL of H_2O is initially at room temperature (22 degree C). A chilled steel rod at 2 degree C is placed in the water. If the final temperature of the system is 21.3 degree C, what is the mass of the steel bar?

Answer 1

the sum of the heats gained is zero.

masssteel*cs*(21.3-2)+masswater*cw*(21.3-22)=0

solve for masssteel. YOu will have to look up the specific heat cs for steel.

Answer 2

8.814