Asked by sean
The launch site for trigon balloon co. is 250 ft above sea level. A hot air balloon is launched from the site and begins to rise at a rate of 110 ft/min. At the same time, another balloon 2200 ft above sea level begins to descend at a rate of 150 ft/min.
A. How long will it be unit the balloons are at the same elevation?
B. What will their elevation be then?
A. How long will it be unit the balloons are at the same elevation?
B. What will their elevation be then?
Answers
Answered by
Reiny
balloon#1 = 250 + 110t
balloon#2 = 2200 - 150t
When they reach the same height,
250 + 110t = 2200 - 150t
260t = 1950
t = 7.5 ----- 7 min, 30 seconds
how high? plug t = 7.5 into either equation, you must get the same result for each case
balloon#2 = 2200 - 150t
When they reach the same height,
250 + 110t = 2200 - 150t
260t = 1950
t = 7.5 ----- 7 min, 30 seconds
how high? plug t = 7.5 into either equation, you must get the same result for each case
Answered by
jessie
I don't under stand how to do 1/3 + 1/10 = what!
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