Asked by sahar
2x^2-5x-12=0
solve by completing the square.
please explain how it's sovled.
solve by completing the square.
please explain how it's sovled.
Answers
Answered by
John
A perfect square is,
(a+b)^2=a^2+b^2+2ab
So you have to adapt the equation given to this expression.
The term with x should be of the form 2ab, but a=sqrt(2)x, so b=5/(2*sqrt(2)), then
2x^2-5x-12=(sqrt(2)*x)^2+sqrt(2)*x*5/(2*sqrt(2))+25/8-25/8-12=0
(sqrt(2)x+5/(2sqrt(2)))^2=121/8
x=4; x=-3/2
(a+b)^2=a^2+b^2+2ab
So you have to adapt the equation given to this expression.
The term with x should be of the form 2ab, but a=sqrt(2)x, so b=5/(2*sqrt(2)), then
2x^2-5x-12=(sqrt(2)*x)^2+sqrt(2)*x*5/(2*sqrt(2))+25/8-25/8-12=0
(sqrt(2)x+5/(2sqrt(2)))^2=121/8
x=4; x=-3/2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.